Java Program to find Matrix Transpose
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Find Matrix Transpose
In the following example, we will transpose the given matrix (two-dimensional array).
Example
Java Compiler
public class myClass
{
public static void main(String[] args)
{
int i, j, n;
int[][] arr = {
{1, 1, 1},
{2, 2, 2},
{3, 3, 3}
};
System.out.println("Matrix (3 x 3):");
for(i=0; i<3; i++)
{
for(j=0; j<3; j++)
System.out.format("%d ", arr[i][j]);
System.out.println();
}
for(i=0; i<3; i++)
{
for(j=i+1; j<3; j++)
{
n = arr[i][j];
arr[i][j] = arr[j][i];
arr[j][i] = n;
}
}
System.out.println("\nMatrix Transpose:");
for(i=0; i<3; i++)
{
for(j=0; j<3; j++)
System.out.format("%d ", arr[i][j]);
System.out.println();
}
}
}
Output
Matrix (3 x 3):
1 1 1
2 2 2
3 3 3
Matrix Transpose:
1 2 3
1 2 3
1 2 3
In the following example, we will get the values for (3 x 3) Matrix from the user and display the transpose matrix.
Example
Java Compiler
import java.util.Scanner;
public class myClass
{
public static void main(String[] args)
{
int i, j, n;
int[][] arr = new int[3][3];
Scanner reader = new Scanner(System.in);
System.out.println("Enter Matrix (3 x 3):");
for(i=0; i<3; i++)
{
for(j=0; j<3; j++)
arr[i][j] = reader.nextInt();
}
for(i=0; i<3; i++)
{
for(j=i+1; j<3; j++)
{
n = arr[i][j];
arr[i][j] = arr[j][i];
arr[j][i] = n;
}
}
System.out.println("\nMatrix Transpose:");
for(i=0; i<3; i++)
{
for(j=0; j<3; j++)
System.out.format("%d ", arr[i][j]);
System.out.println();
}
}
}
Output
Enter Matrix (3 x 3):
2 2 2
4 4 4
6 6 6
Matrix Transpose:
2 4 6
2 4 6
2 4 6
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